5.3 The Fundamental Theorem of Calculus/19: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 1: | Line 1: | ||
<math>\begin{align}\int_{-1}^{2}(x^3-2x)dx &=\frac{x^4}{4}-\frac{2x^2}{2}\Bigg|_{-1}^{2}&=\frac{(2)^4}{4}-\frac{2(2)^2}{2}\end{align}</math> | <math>\begin{align}\int_{-1}^{2}(x^3-2x)dx &=\frac{x^4}{4}-\frac{2x^2}{2}\Bigg|_{-1}^{2} \\[2ex]&=\frac{(2)^4}{4}-\frac{2(2)^2}{2}\end{align}</math> | ||
Revision as of 19:31, 25 August 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align}\int_{-1}^{2}(x^3-2x)dx &=\frac{x^4}{4}-\frac{2x^2}{2}\Bigg|_{-1}^{2} \\[2ex]&=\frac{(2)^4}{4}-\frac{2(2)^2}{2}\end{align}}