5.3 The Fundamental Theorem of Calculus/41: Difference between revisions

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\int\limits_{0}^{\pi}f(x)dx
\int\limits_{0}^{\pi}f(x)dx
\quad \text{where} \;
\quad \text{where} \;
f(x) = \begin{cases}
 
     1 & -1 \le x < 0 \\
f(x) =
     1 - x^2 & \text{otherwise}
  \begin{cases}
     sin(x) & 0 \le x < \pi/2 \\
     cos(x) & \pi/2 \le x \le \pi
   \end{cases}
   \end{cases}




</math>
</math>

Revision as of 19:30, 25 August 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int \limits _{0}^{\pi }f(x)dx\quad {\text{where}}\;f(x)={\begin{cases}sin(x)&0\leq x<\pi /2\\cos(x)&\pi /2\leq x\leq \pi \end{cases}}}