5.3 The Fundamental Theorem of Calculus/19: Difference between revisions

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<math>\begin{align}int_{-1}^{2}\(x^3-2x)dx &=\frac{x^4}{4}-\frac{2x^2}{2}\Bigg|_{-1}^{2}\end{align}</math>
<math>\begin{align}int_{-1}^{2}(x^3-2x)dx &=\frac{x^4}{4}-\frac{2x^2}{2}\Bigg|_{-1}^{2}\end{align}</math>

Revision as of 19:26, 25 August 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}int_{-1}^{2}(x^{3}-2x)dx&={\frac {x^{4}}{4}}-{\frac {2x^{2}}{2}}{\Bigg |}_{-1}^{2}\end{aligned}}}