5.3 The Fundamental Theorem of Calculus/15: Difference between revisions
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\begin{align} | \begin{align} | ||
y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec</math> | y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec | ||
\end{align} | |||
</math> | |||
Revision as of 19:15, 25 August 2022
Use part 1 of the FTC to find the derivative of the function:
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}y=\int _{0}^{tan(x)}{\sqrt {t+{\sqrt {t}}}}dt=\sec \end{aligned}}}