5.3 The Fundamental Theorem of Calculus/37: Difference between revisions

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using the rule we get  
using the rule we get  
<math>6sin^(-1)(x)\bigg|_{1/2}^{\sqrt{3}/2}</math>
<math>6sin^-1(x)\bigg|_{1/2}^{\sqrt{3}/2}</math>


[[5.3 The Fundamental Theorem of Calculus/1|1]]
[[5.3 The Fundamental Theorem of Calculus/1|1]]

Revision as of 19:08, 25 August 2022

FTC # 2- the is F(b)-F(a) where F is the antiderivitive of f such that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle F^\prime=f}

37) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int\limits_{1/2}^{\sqrt{3})/2}\frac{6}{\sqrt{1-t^2}} dt }

using the rule we get Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle 6sin^-1(x)\bigg|_{1/2}^{\sqrt{3}/2}}

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