5.3 The Fundamental Theorem of Calculus/37: Difference between revisions
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37) <math>\int\limits_{1/2}^{(\sqrt{3})/2}\frac{6}{(\sqrt{1-t^2})} dt </math> | 37) <math>\int\limits_{1/2}^{(\sqrt{3})/2}\frac{6}{(\sqrt{1-t^2})} dt </math> | ||
using the rule we get 6sin^-1(x) | using the rule we get | ||
<math>6sin^-1(x)</math> | |||
[[5.3 The Fundamental Theorem of Calculus/1|1]] | [[5.3 The Fundamental Theorem of Calculus/1|1]] | ||
Revision as of 19:02, 25 August 2022
FTC # 2- the Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{d}{dx}[\int\limits_{a(x)}^{b(x)}F(x)dx]} is F(b)-F(a) where F is the antiderivitive of f such that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle F^\prime=f}
37) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int\limits_{1/2}^{(\sqrt{3})/2}\frac{6}{(\sqrt{1-t^2})} dt }
using the rule we get Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle 6sin^-1(x)}
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