5.3 The Fundamental Theorem of Calculus/41: Difference between revisions

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\int\limits_{0}^{\pi}f(x)dx
\int\limits_{0}^{\pi}f(x)dx
\text{ where}
\text{where}
f(x) = \begin{cases}
f(x) = \begin{cases}
     1 & -1 \le x < 0 \\
     1 & -1 \le x < 0 \\

Revision as of 19:00, 25 August 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int\limits_{0}^{\pi}f(x)dx \text{where} f(x) = \begin{cases} 1 & -1 \le x < 0 \\ \frac{1}{2} & x = 0 \\ 1 - x^2 & \text{otherwise} \end{cases} }