5.3 The Fundamental Theorem of Calculus/37: Difference between revisions

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FTC # 2
FTC # 2
<math>int\limits_{1/2}^{(\sqrt{3})/2}\frac{6}{(\sqrt{1-x^2})} du </math>
<math>\int\limits_{1/2}^{(\sqrt{3})/2}\frac{6}{(\sqrt{1-x^2})} du </math>


[[5.3 The Fundamental Theorem of Calculus/1|1]]
[[5.3 The Fundamental Theorem of Calculus/1|1]]

Revision as of 18:57, 25 August 2022

FTC # 2 Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int \limits _{1/2}^{({\sqrt {3}})/2}{\frac {6}{({\sqrt {1-x^{2}}})}}du}

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