5.3 The Fundamental Theorem of Calculus/9: Difference between revisions
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<math>g(y)= \int_{y}^{2}t^2\sin{(t)}dt = 1(y^{2}sin{y})-0(2^{2}sin{(2)})= y^{2} sin{(y)} </math> | <math>g(y)= \int_{y}^{2}t^2\sin{(t)}dt = 1(y^{2}sin{(y)})-0(2^{2}sin{(2)})= y^{2} sin{(y)} </math> | ||
Revision as of 16:26, 25 August 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle g(y)=\int _{y}^{2}t^{2}\sin {(t)}dt=1(y^{2}sin{(y)})-0(2^{2}sin{(2)})=y^{2}sin{(y)}}