7.1 Integration By Parts/11: Revision history

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29 November 2022

24 November 2022

  • curprev 04:2804:28, 24 November 2022‎ Nubiaa92222@students.laalliance.org talk contribs‎ 658 bytes +658‎ Created page with "<math> \int(arctan (4t)) dt </math> <math> \begin{align} \pi\int_1^2\left[\left(2-\frac{1}{2}x\right)^2\right]dx & = \pi\int_1^2\left[\left(4-2x+\frac{1}{4}x^2\right)\right]dx \\[2ex] &= \pi\left[4x-x^2+\frac{1}{12}x^3\right]\Bigg|_1^2 \\[2ex] &= \pi\left[\left(4(2)-(2)^2+\frac{1}{12}(2)^3\right)-\left(4(1)-(1)^2+\frac{1}{12}(1)^3\right)\right] \\[2ex] &= \pi\left[\left(8-4+\frac{8}{12}\right)-\left(4-1+\frac{1}{12}\right)\right] \\[2ex] &= \pi\left[4+\frac{8}{12}-3-\f..."
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