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	<title>7.1 Integration By Parts/51 - Revision history</title>
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	<updated>2026-05-05T23:03:58Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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		<id>https://wiki.dvaezazizi.com/index.php?title=7.1_Integration_By_Parts/51&amp;diff=5647&amp;oldid=prev</id>
		<title>Elizabethh58413: Created page with &quot;&lt;math&gt; \text{use Exercise 47 to evaluate} \int(\ln{x})^3dx &lt;/math&gt; &lt;br&gt;&lt;br&gt; &lt;math&gt; \text{Exercise 47:}\qquad x(\ln{x})^n-n\int(\ln{x})^{n-1}dx &lt;/math&gt; &lt;br&gt;&lt;br&gt; &lt;math&gt; \int(\ln{x})^3dx= x(\ln{x})^3-3\int(\ln{x})^2dx &lt;/math&gt; &lt;br&gt;&lt;br&gt; &lt;math&gt; u = (\ln{x})^2  \qquad dv = dx &lt;/math&gt; &lt;br&gt;&lt;br&gt; &lt;math&gt; du = 2\frac{1}{x}\ln{x}dx \qquad v = x &lt;/math&gt; &lt;br&gt;&lt;br&gt;  &lt;math&gt; \begin{align} \int(\ln{x})^3dx &amp;= x(\ln{x})^3-3\int(\ln{x})^2dx = x(\ln{x})^3-3[x(\ln{x})^2 - 2\int(\ln{x})dx]  \\[2e...&quot;</title>
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		<updated>2022-11-29T03:55:56Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;&amp;lt;math&amp;gt; \text{use Exercise 47 to evaluate} \int(\ln{x})^3dx &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt; &amp;lt;math&amp;gt; \text{Exercise 47:}\qquad x(\ln{x})^n-n\int(\ln{x})^{n-1}dx &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt; &amp;lt;math&amp;gt; \int(\ln{x})^3dx= x(\ln{x})^3-3\int(\ln{x})^2dx &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt; &amp;lt;math&amp;gt; u = (\ln{x})^2  \qquad dv = dx &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt; &amp;lt;math&amp;gt; du = 2\frac{1}{x}\ln{x}dx \qquad v = x &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;  &amp;lt;math&amp;gt; \begin{align} \int(\ln{x})^3dx &amp;amp;= x(\ln{x})^3-3\int(\ln{x})^2dx = x(\ln{x})^3-3[x(\ln{x})^2 - 2\int(\ln{x})dx]  \\[2e...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;&amp;lt;math&amp;gt; \text{use Exercise 47 to evaluate} \int(\ln{x})^3dx &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt; \text{Exercise 47:}\qquad x(\ln{x})^n-n\int(\ln{x})^{n-1}dx &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt;&lt;br /&gt;
\int(\ln{x})^3dx= x(\ln{x})^3-3\int(\ln{x})^2dx &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt; u = (\ln{x})^2  \qquad dv = dx &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt; du = 2\frac{1}{x}\ln{x}dx \qquad v = x &amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;&lt;br /&gt;
\begin{align}&lt;br /&gt;
\int(\ln{x})^3dx &amp;amp;= x(\ln{x})^3-3\int(\ln{x})^2dx = x(\ln{x})^3-3[x(\ln{x})^2 - 2\int(\ln{x})dx]  \\[2ex]&lt;br /&gt;
&amp;amp;=  x(\ln{x})^3-3[x(\ln{x})^2 -2(x\ln{x} - \int1dx) =  x(\ln{x})^3-3[x(\ln{x})^2 -2x\ln{x} + 2x] \\[2ex]&lt;br /&gt;
&amp;amp; =x(\ln{x})^3 - 3x(\ln{x})^2+ 6x\ln{x} - 6x +c \\[2ex]&lt;br /&gt;
\end{align}&lt;br /&gt;
&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Elizabethh58413</name></author>
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