6.2 Volumes/7 - Revision history

Arianac101603@students.laalliance.org at 20:46, 29 November 2022

2022-11-29T20:46:16Z

← Older revision		Revision as of 20:46, 29 November 2022
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	<math>=\pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg\|_{0}^{1}</math>		<math>=\pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg\|_{0}^{1}</math>

	<math>=\pi(\frac{1}{3}-\frac{1}{7})</math> <math>=\frac{7\pi}{21}-\frac{~~3pi~~}{21}</math> <math>=\frac{~~4pi~~}{21}</math>		<math>=\pi(\frac{1}{3}-\frac{1}{7})</math> <math>=\frac{7\pi}{21}-\frac{3\pi}{21}</math> <math>=\frac{4\pi}{21}</math>

Arianac101603@students.laalliance.org at 20:45, 29 November 2022

2022-11-29T20:45:58Z

← Older revision		Revision as of 20:45, 29 November 2022
Line 7:		Line 7:
	<math>=\pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg\|_{0}^{1}</math>		<math>=\pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg\|_{0}^{1}</math>

	<math>=\pi(\frac{1}{3}-\frac{1}{7})</math> <math>=\frac{~~7pi~~}{21}-\frac{3pi}{21}</math> <math>=\frac{4pi}{21}</math>		<math>=\pi(\frac{1}{3}-\frac{1}{7})</math> <math>=\frac{7\pi}{21}-\frac{3pi}{21}</math> <math>=\frac{4pi}{21}</math>

Arianac101603@students.laalliance.org at 20:45, 29 November 2022

2022-11-29T20:45:13Z

← Older revision		Revision as of 20:45, 29 November 2022
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	<math>y=x^{3}</math>, <math>y=x</math>, (x-axis)		<math>y=x^{3}</math>, <math>y=x</math>, (x-axis)

	<math>pi\int_{0}^{1}\left((x)^2-(x^3)^2)\right)dx</math>		<math>\pi\int_{0}^{1}\left((x)^2-(x^3)^2)\right)dx</math>

	<math>=(pi)\int_{0}^{1}\left((x^2-x^6)\right)dx</math>		<math>=(\pi)\int_{0}^{1}\left((x^2-x^6)\right)dx</math>

	<math>=pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg\|_{0}^{1}</math>		<math>=\pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg\|_{0}^{1}</math>

	<math>=pi(\frac{1}{3}-\frac{1}{7})</math> <math>=\frac{7pi}{21}-\frac{3pi}{21}</math> <math>=\frac{4pi}{21}</math>		<math>=\pi(\frac{1}{3}-\frac{1}{7})</math> <math>=\frac{7pi}{21}-\frac{3pi}{21}</math> <math>=\frac{4pi}{21}</math>

Arianac101603@students.laalliance.org: Created page with " $y=x^{3}$ , $y=x$ , (x-axis) $pi\int_{0}^{1}\left((x)^2-(x^3)^2)\right)dx$ $=(pi)\int_{0}^{1}\left((x^2-x^6)\right)dx$ $=pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg|_{0}^{1}$ $=pi(\frac{1}{3}-\frac{1}{7})$ $=\frac{7pi}{21}-\frac{3pi}{21}$ $=\frac{4pi}{21}$ "

2022-11-29T04:37:09Z

Created page with "<math>y=x^{3}</math>, <math>y=x</math>, (x-axis) <math>pi\int_{0}^{1}\left((x)^2-(x^3)^2)\right)dx</math> <math>=(pi)\int_{0}^{1}\left((x^2-x^6)\right)dx</math> <math>=pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg|_{0}^{1}</math> <math>=pi(\frac{1}{3}-\frac{1}{7})</math> <math>=\frac{7pi}{21}-\frac{3pi}{21}</math> <math>=\frac{4pi}{21}</math>"

New page

<math>y=x^{3}</math>, <math>y=x</math>, (x-axis)

<math>pi\int_{0}^{1}\left((x)^2-(x^3)^2)\right)dx</math>

<math>=(pi)\int_{0}^{1}\left((x^2-x^6)\right)dx</math>

<math>=pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg|_{0}^{1}</math>

<math>=pi(\frac{1}{3}-\frac{1}{7})</math> <math>=\frac{7pi}{21}-\frac{3pi}{21}</math> <math>=\frac{4pi}{21}</math>

6.2 Volumes/7 - Revision history

Arianac101603@students.laalliance.org at 20:46, 29 November 2022

Arianac101603@students.laalliance.org at 20:45, 29 November 2022

Arianac101603@students.laalliance.org at 20:45, 29 November 2022

Arianac101603@students.laalliance.org: Created page with "y=x^{3}, y=x, (x-axis) pi\int_{0}^{1}\left((x)^2-(x^3)^2)\right)dx =(pi)\int_{0}^{1}\left((x^2-x^6)\right)dx =pi(\frac{x^3}{3}-\frac{x^7}{7})\bigg|_{0}^{1} =pi(\frac{1}{3}-\frac{1}{7}) =\frac{7pi}{21}-\frac{3pi}{21} =\frac{4pi}{21}"