6.2 Trigonometric Functions: Unit Circle Approach/79 - Revision history

Kevind75816@students.laalliance.org at 16:12, 7 September 2022

2022-09-07T16:12:39Z

← Older revision		Revision as of 16:12, 7 September 2022
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	<math> \theta \rightarrow x=2, \, y=-3, \, r= \sqrt{13} </math><br><br>		<math> \theta \rightarrow x=2, \, y=-3, \, r= \sqrt{13} </math><br><br>

	~~<math> -3^2 + 4^2 = 5^2 </math><br><br>~~
	~~<math> 9 + 16 = 25 </math><br><br>~~
	~~<math>\sqrt{25} = 5 = r </math><br><br>~~
	<math>		<math>
	\begin{align}		\begin{align}

Kevind75816@students.laalliance.org at 16:06, 7 September 2022

2022-09-07T16:06:07Z

← Older revision		Revision as of 16:06, 7 September 2022
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	\sin{(\theta)} &= -\frac{3\sqrt{13}}{13} & \csc{(\theta)} &= -\frac{\sqrt{13}}{3}\\[2ex]		\sin{(\theta)} &= -\frac{3\sqrt{13}}{13} & \csc{(\theta)} &= -\frac{\sqrt{13}}{3}\\[2ex]

	\cos{(\theta)} &= \frac{2\sqrt{13}}{13} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]		\cos{(\theta)} &= \frac{2\sqrt{13}}{13} & \sec{(\theta)} &= \frac{\sqrt{13}}{2}\\[2ex]

	\tan{(\theta)} &= \frac{-3}{2} & \cot{(\theta)} &= \frac{-2}{3} \\[2ex]		\tan{(\theta)} &= \frac{-3}{2} & \cot{(\theta)} &= \frac{-2}{3} \\[2ex]

Kevind75816@students.laalliance.org at 16:04, 7 September 2022

2022-09-07T16:04:57Z

← Older revision		Revision as of 16:04, 7 September 2022
Line 11:		Line 11:
	\sin{(\theta)} &= -\frac{3\sqrt{13}}{13} & \csc{(\theta)} &= -\frac{\sqrt{13}}{3}\\[2ex]		\sin{(\theta)} &= -\frac{3\sqrt{13}}{13} & \csc{(\theta)} &= -\frac{\sqrt{13}}{3}\\[2ex]

	\cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]		\cos{(\theta)} &= \frac{2\sqrt{13}}{13} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]

	\tan{(\theta)} &= \frac{-3}{2} & \cot{(\theta)} &= \frac{-2}{3} \\[2ex]		\tan{(\theta)} &= \frac{-3}{2} & \cot{(\theta)} &= \frac{-2}{3} \\[2ex]

Kevind75816@students.laalliance.org at 16:01, 7 September 2022

2022-09-07T16:01:10Z

← Older revision		Revision as of 16:01, 7 September 2022
Line 9:		Line 9:
	\begin{align}		\begin{align}

	\sin{(\theta)} &= \frac{4}{5} & \csc{(\theta)} &= -\frac{\sqrt{13}}{3}\\[2ex]		\sin{(\theta)} &= -\frac{3\sqrt{13}}{13} & \csc{(\theta)} &= -\frac{\sqrt{13}}{3}\\[2ex]

	\cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]		\cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]

Kevind75816@students.laalliance.org at 15:57, 7 September 2022

2022-09-07T15:57:37Z

← Older revision		Revision as of 15:57, 7 September 2022
Line 9:		Line 9:
	\begin{align}		\begin{align}

	\sin{(\theta)} &= \frac{4}{5} & \csc{(\theta)} &= \frac{5}{4}\\[2ex]		\sin{(\theta)} &= \frac{4}{5} & \csc{(\theta)} &= -\frac{\sqrt{13}}{3}\\[2ex]

	\cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]		\cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]

	\tan{(\theta)} &= \frac{-3}{2} & \cot{(\theta)} &= \frac{-3}{4} \\[2ex]		\tan{(\theta)} &= \frac{-3}{2} & \cot{(\theta)} &= \frac{-2}{3} \\[2ex]


	\end{align}		\end{align}
	</math>		</math>

Kevind75816@students.laalliance.org at 15:56, 7 September 2022

2022-09-07T15:56:34Z

← Older revision		Revision as of 15:56, 7 September 2022
Line 13:		Line 13:
	\cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]		\cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]

	\tan{(\theta)} &= \frac{4}{-3} & \cot{(\theta)} &= \frac{-3}{4} \\[2ex]		\tan{(\theta)} &= \frac{-3}{2} & \cot{(\theta)} &= \frac{-3}{4} \\[2ex]


	\end{align}		\end{align}
	</math>		</math>

Kevind75816@students.laalliance.org at 15:50, 7 September 2022

2022-09-07T15:50:48Z

← Older revision		Revision as of 15:50, 7 September 2022
Line 1:		Line 1:


	<math> \theta \rightarrow x=2, \, y=-3, \, r= \sqrt{3} </math><br><br>		<math> \theta \rightarrow x=2, \, y=-3, \, r= \sqrt{13} </math><br><br>

	<math> -3^2 + 4^2 = 5^2 </math><br><br>		<math> -3^2 + 4^2 = 5^2 </math><br><br>

Kevind75816@students.laalliance.org at 15:49, 7 September 2022

2022-09-07T15:49:48Z

← Older revision		Revision as of 15:49, 7 September 2022
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	<math> \theta \rightarrow x=-3, \, y=4, \, r=5 </math><br><br>		<math> \theta \rightarrow x=2, \, y=-3, \, r= \sqrt{3} </math><br><br>

	<math> -3^2 + 4^2 = 5^2 </math><br><br>		<math> -3^2 + 4^2 = 5^2 </math><br><br>

Kevind75816@students.laalliance.org: Created page with " $\theta \rightarrow x=-3, \, y=4, \, r=5$

$-3^2 + 4^2 = 5^2$

$9 + 16 = 25$

$\sqrt{25} = 5 = r$

$\begin{align} \sin{(\theta)} &= \frac{4}{5} & \csc{(\theta)} &= \frac{5}{4}\\[2ex] \cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex] \tan{(\theta)} &= \frac{4}{-3} & \cot{(\theta)} &= \frac{-3}{4} \\[2ex] \end{align}$ "

2022-09-07T15:49:04Z

Created page with " <math> \theta \rightarrow x=-3, \, y=4, \, r=5 </math> <math> -3^2 + 4^2 = 5^2 </math> <math> 9 + 16 = 25 </math> <math>\sqrt{25} = 5 = r </math> <math> \begin{align} \sin{(\theta)} &= \frac{4}{5} & \csc{(\theta)} &= \frac{5}{4}\\[2ex] \cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex] \tan{(\theta)} &= \frac{4}{-3} & \cot{(\theta)} &= \frac{-3}{4} \\[2ex] \end{align} </math>"

New page

<math> \theta \rightarrow x=-3, \, y=4, \, r=5 </math> 

<math> -3^2 + 4^2 = 5^2 </math> 
<math> 9 + 16 = 25 </math> 
<math>\sqrt{25} = 5 = r </math> 
<math>
\begin{align}

\sin{(\theta)} &= \frac{4}{5} & \csc{(\theta)} &= \frac{5}{4}\\[2ex]

\cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]

\tan{(\theta)} &= \frac{4}{-3} & \cot{(\theta)} &= \frac{-3}{4} \\[2ex]

\end{align}
</math>