Manuelg70564@students.laalliance.org: Created page with " $\theta \rightarrow x=-3, \, y=4, \, r=5$

$-3^2 + 4^2 = 5^2$

$9 + 16 = 25$

$\sqrt{25} = 5 = r$

$\begin{align} \sin{(\theta)} &= \frac{4}{5} & \csc{(\theta)} &= \frac{5}{4}\\[2ex] \cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex] \tan{(\theta)} &= \frac{4}{-3} & \cot{(\theta)} &= \frac{-3}{4} \\[2ex] \end{align}$ "

2022-09-06T01:14:12Z

Created page with " <math> \theta \rightarrow x=-3, \, y=4, \, r=5 </math> <math> -3^2 + 4^2 = 5^2 </math> <math> 9 + 16 = 25 </math> <math>\sqrt{25} = 5 = r </math> <math> \begin{align} \sin{(\theta)} &= \frac{4}{5} & \csc{(\theta)} &= \frac{5}{4}\\[2ex] \cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex] \tan{(\theta)} &= \frac{4}{-3} & \cot{(\theta)} &= \frac{-3}{4} \\[2ex] \end{align} </math>"

New page

<math> \theta \rightarrow x=-3, \, y=4, \, r=5 </math> 

<math> -3^2 + 4^2 = 5^2 </math> 
<math> 9 + 16 = 25 </math> 
<math>\sqrt{25} = 5 = r </math> 
<math>
\begin{align}

\sin{(\theta)} &= \frac{4}{5} & \csc{(\theta)} &= \frac{5}{4}\\[2ex]

\cos{(\theta)} &= \frac{-3}{5} & \sec{(\theta)} &= \frac{5}{-3}\\[2ex]

\tan{(\theta)} &= \frac{4}{-3} & \cot{(\theta)} &= \frac{-3}{4} \\[2ex]

\end{align}
</math>

6.2 Trigonometric Functions: Unit Circle Approach/77 - Revision history