6.2 Trigonometric Functions: Unit Circle Approach/57 - Revision history

Christophers69344@students.laalliance.org at 19:53, 29 August 2022

2022-08-29T19:53:59Z

← Older revision		Revision as of 19:53, 29 August 2022
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	-\frac {\pi}{6}= -30^{\circ}</math><br>		-\frac {\pi}{6}= -30^{\circ}</math><br>
	<math> 360^{\circ} -30^{\circ} = 330^{\circ} = \frac{\sqrt{3}}{2} , -\frac{1}{2}</math><br>		<math> 360^{\circ} -30^{\circ} = 330^{\circ} = \frac{\sqrt{3}}{2} , -\frac{1}{2}</math><br>
	<math>cos(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{1} = \frac{\sqrt{3}}{2}</math><br>		<math>cos(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{\cancel{1}} = \frac{\sqrt{3}}{2}</math><br>
	<math>sin(-\frac {\pi}{6})= \frac{-\frac{1}{2}}{1} = -\frac{1}{2}</math><br>		<math>sin(-\frac {\pi}{6})= \frac{-\frac{1}{2}}{\cancel{1}} = -\frac{1}{2}</math><br>
	<math>tan(-\frac {\pi}{6})= \frac{-\frac{1}{2}}{\frac{\sqrt{3}}{2}}\cdot(2) = -\frac{1}{\sqrt{3}} \cdot ({\sqrt{3}}) = \frac{-\sqrt{3}}{3}</math><br>		<math>tan(-\frac {\pi}{6})= \frac{-\frac{1}{\cancel{2}}}{\frac{\sqrt{3}}{\cancel{2}}}\cdot(2) = -\frac{1}{\sqrt{3}} \cdot ({\sqrt{3}}) = \frac{-\sqrt{3}}{3}</math><br>
	<math>sec(-\frac {\pi}{6})= \frac{1}{\frac{\sqrt{3}}{2}} \cdot (2) = \frac{2}{\sqrt{3}} \cdot (\sqrt{3}) = \frac {2\sqrt{3}}{3}</math><br>		<math>sec(-\frac {\pi}{6})= \frac{1}{\frac{\sqrt{3}}{\cancel{2}}} \cdot (2) = \frac{2}{\sqrt{3}} \cdot (\sqrt{3}) = \frac {2\sqrt{3}}{3}</math><br>
	<math>csc(-\frac {\pi}{6})= \frac{1}{-\frac{1}{2}} \cdot (2) = \frac{2}{-1} = -2 </math><br>		<math>csc(-\frac {\pi}{6})= \frac{1}{-\frac{1}{\cancel{2}}} \cdot (2) = \frac{2}{-1} = -2 </math><br>
	<math>cot(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} \cdot (2) = \frac{\frac{2}{\sqrt{3}}}{-2} = -\sqrt{3}</math><br>		<math>cot(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} \cdot (2) = \frac{\frac{2}{\sqrt{3}}}{-2} = -\sqrt{3}</math><br>

Christophers69344@students.laalliance.org at 19:49, 29 August 2022

2022-08-29T19:49:44Z

← Older revision		Revision as of 19:49, 29 August 2022
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	<math>sec(-\frac {\pi}{6})= \frac{1}{\frac{\sqrt{3}}{2}} \cdot (2) = \frac{2}{\sqrt{3}} \cdot (\sqrt{3}) = \frac {2\sqrt{3}}{3}</math><br>		<math>sec(-\frac {\pi}{6})= \frac{1}{\frac{\sqrt{3}}{2}} \cdot (2) = \frac{2}{\sqrt{3}} \cdot (\sqrt{3}) = \frac {2\sqrt{3}}{3}</math><br>
	<math>csc(-\frac {\pi}{6})= \frac{1}{-\frac{1}{2}} \cdot (2) = \frac{2}{-1} = -2 </math><br>		<math>csc(-\frac {\pi}{6})= \frac{1}{-\frac{1}{2}} \cdot (2) = \frac{2}{-1} = -2 </math><br>
	<math>cot(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} \cdot (2) = \frac{\frac{2}{\sqrt{3}}{-2} = -\sqrt{3}</math><br>		<math>cot(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} \cdot (2) = \frac{\frac{2}{\sqrt{3}}}{-2} = -\sqrt{3}</math><br>

Christophers69344@students.laalliance.org at 16:27, 29 August 2022

2022-08-29T16:27:37Z

← Older revision		Revision as of 16:27, 29 August 2022
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	<math>		<math>
	-\frac {\pi}{6}= -30^{\circ}<\math><br>		-\frac {\pi}{6}= -30^{\circ}</math><br>
			<math> 360^{\circ} -30^{\circ} = 330^{\circ} = \frac{\sqrt{3}}{2} , -\frac{1}{2}</math><br>
	-90^{\circ}\~~cdot~~\frac{\pi}{~~180^~~{\~~circ~~}}=\frac{\~~cancel~~{2}\cdot \~~cancel~~{5} \cdot \~~cancel~~{3}\~~cdot~~ \~~cancel~~{3}}{1}~~\cdot~~\frac{\pi}{{2}\cdot \~~cancel~~{2} \cdot \~~cancel~~{5} \~~cdot~~ \~~cancel~~{3} \~~cdot~~ \~~cancel~~{3}}\cdot{-1}		<math>cos(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{1} = \frac{\sqrt{3}}{2}</math><br>
	= -\frac{\pi}{2}		<math>sin(-\frac {\pi}{6})= \frac{-\frac{1}{2}}{1} = -\frac{1}{2}</math><br>
			<math>tan(-\frac {\pi}{6})= \frac{-\frac{1}{2}}{\frac{\sqrt{3}}{2}}\cdot(2) = -\frac{1}{\sqrt{3}} \cdot ({\sqrt{3}}) = \frac{-\sqrt{3}}{3}</math><br>
	</math>		<math>sec(-\frac {\pi}{6})= \frac{1}{\frac{\sqrt{3}}{2}} \cdot (2) = \frac{2}{\sqrt{3}} \cdot (\sqrt{3}) = \frac {2\sqrt{3}}{3}</math><br>
			<math>csc(-\frac {\pi}{6})= \frac{1}{-\frac{1}{2}} \cdot (2) = \frac{2}{-1} = -2 </math><br>
			<math>cot(-\frac {\pi}{6})= \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} \cdot (2) = \frac{\frac{2}{\sqrt{3}}{-2} = -\sqrt{3}</math><br>

Christophers69344@students.laalliance.org: Created page with " $-\frac {\pi}{6}= -30^{\circ}<\math> -90^{\circ}\cdot\frac{\pi}{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{5} \cdot \cancel{3}\cdot \cancel{3}}{1}\cdot\frac{\pi}{{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot \cancel{3}}\cdot{-1} = -\frac{\pi}{2}$ "

2022-08-28T02:47:52Z

Created page with "<math> -\frac {\pi}{6}= -30^{\circ}<\math><br> -90^{\circ}\cdot\frac{\pi}{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{5} \cdot \cancel{3}\cdot \cancel{3}}{1}\cdot\frac{\pi}{{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot \cancel{3}}\cdot{-1} = -\frac{\pi}{2} </math>"

New page

<math>
-\frac {\pi}{6}= -30^{\circ}<\math><br>

-90^{\circ}\cdot\frac{\pi}{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{5} \cdot \cancel{3}\cdot \cancel{3}}{1}\cdot\frac{\pi}{{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot \cancel{3}}\cdot{-1}
= -\frac{\pi}{2}

</math>