6.2 Trigonometric Functions: Unit Circle Approach/32 - Revision history

Dvaezazizi@laalliance.org: Protected "6.2 Trigonometric Functions: Unit Circle Approach/32" ([Edit=Allow only administrators] (indefinite) [Move=Allow only administrators] (indefinite))

2022-08-25T22:19:58Z

Protected "6.2 Trigonometric Functions: Unit Circle Approach/32" ([Edit=Allow only administrators] (indefinite) [Move=Allow only administrators] (indefinite))

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Revision as of 22:19, 25 August 2022

2022-08-25T22:14:31Z

← Older revision		Revision as of 22:14, 25 August 2022
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	<math>		<math>
	\sin(30^{\circ})-\cos(45^{\circ}) = \frac{1}{2} - \frac{\sqrt{2}}{2} =		\sin(30^{\circ})-\cos(45^{\circ}) = \frac{1}{2} - \frac{\sqrt{2}}{2} = \frac{1-\sqrt{2}}{2}

	</math>		</math>

2022-08-25T22:14:16Z

← Older revision		Revision as of 22:14, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	\sin(30^{\circ})-\cos(45^{\circ}) = \frac{1}{2} - \frac{\sqrt{2}}{2} = ~~\frac{1-\sqrt{2}}{2}~~		\sin(30^{\circ})-\cos(45^{\circ}) = \frac{1}{2} - \frac{\sqrt{2}}{2} =

	</math>		</math>

2022-08-25T22:13:54Z

← Older revision		Revision as of 22:13, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	\sin(30^{\circ})-\cos(45^{\circ}) = \frac{1}{2} - \frac{\sqrt{2}}{2}		\sin(30^{\circ})-\cos(45^{\circ}) = \frac{1}{2} - \frac{\sqrt{2}}{2} = \frac{1-\sqrt{2}}{2}

	</math>		</math>

2022-08-25T22:13:30Z

← Older revision		Revision as of 22:13, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	\sin(30^{\circ})-\cos(45^{\circ}) = \frac{1}{2} - \frac{\sqrt(2)}{2}		\sin(30^{\circ})-\cos(45^{\circ}) = \frac{1}{2} - \frac{\sqrt{2}}{2}

	</math>		</math>

2022-08-25T22:13:21Z

← Older revision		Revision as of 22:13, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	\sin(30^{\circ})-\cos(45^{\circ}) =		\sin(30^{\circ})-\cos(45^{\circ}) = \frac{1}{2} - \frac{\sqrt(2)}{2}

	</math>		</math>

2022-08-25T22:12:36Z

Created page with "<math> \sin(30^{\circ})-\cos(45^{\circ}) = </math>"

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