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6.2 Trigonometric Functions: Unit Circle Approach/31 - Revision history
2026-05-05T17:17:45Z
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Hannag101602@students.laalliance.org at 03:34, 31 August 2022
2022-08-31T03:34:31Z
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Hannag101602@students.laalliance.org at 03:34, 31 August 2022
2022-08-31T03:34:22Z
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Hannag101602@students.laalliance.org at 03:33, 31 August 2022
2022-08-31T03:33:46Z
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Hannag101602@students.laalliance.org at 03:33, 31 August 2022
2022-08-31T03:33:04Z
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 03:33, 31 August 2022</td>
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<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><math> \sin(45^{\circ})+\cos(60^{\circ}) = \frac{\sqrt{2}}{2} + \frac{1}{2} = \frac{1}{2}</div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><math> \sin(45^{\circ})+\cos(60^{\circ}) = \frac{\sqrt{2}}{2} + \frac{1}{2} = \frac{1}{2} <ins style="font-weight: bold; text-decoration: none;">\&middot;</ins></div></td></tr>
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Hannag101602@students.laalliance.org at 03:30, 31 August 2022
2022-08-31T03:30:13Z
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 03:30, 31 August 2022</td>
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<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><math> \sin(45^{\circ})+\cos(60^{\circ}) = \frac{\sqrt{2}}{2} + \frac{1}{2} = \frac{1}{2} <del style="font-weight: bold; text-decoration: none;">\{sqrt{2}} + 1</del></div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><math> \sin(45^{\circ})+\cos(60^{\circ}) = \frac{\sqrt{2}}{2} + \frac{1}{2} = \frac{1}{2}</div></td></tr>
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Hannag101602@students.laalliance.org at 03:29, 31 August 2022
2022-08-31T03:29:27Z
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 03:29, 31 August 2022</td>
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<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><math> \sin(45^{\circ})+\cos(60^{\circ}) = \frac{\sqrt{2}}{2} + \frac{1}{2} = \frac{1}{2}</div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><math> \sin(45^{\circ})+\cos(60^{\circ}) = \frac{\sqrt{2}}{2} + \frac{1}{2} = \frac{1}{2} <ins style="font-weight: bold; text-decoration: none;">\{sqrt{2}} + 1</ins></div></td></tr>
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Hannag101602@students.laalliance.org at 03:27, 31 August 2022
2022-08-31T03:27:54Z
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Hannag101602@students.laalliance.org at 03:27, 31 August 2022
2022-08-31T03:27:39Z
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Hannag101602@students.laalliance.org at 03:26, 31 August 2022
2022-08-31T03:26:54Z
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Hannag101602@students.laalliance.org at 03:26, 31 August 2022
2022-08-31T03:26:13Z
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 03:26, 31 August 2022</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l1">Line 1:</td>
<td colspan="2" class="diff-lineno">Line 1:</td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div><math> \sin(45^{\circ})+\cos(60^{\circ}) = \frac{1}{2} - \frac{\sqrt{2}}{2} = \frac{1-\sqrt{2}}{2}</div></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div><math> \sin(45^{\circ})+\cos(60^{\circ}) = \frac{1}{2} - \frac{\sqrt{2}}{2} = \frac{1-\sqrt{2}}{2}</div></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><math<del style="font-weight: bold; text-decoration: none;">/</del>></div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><<ins style="font-weight: bold; text-decoration: none;">/</ins>math></div></td></tr>
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