6.2 Trigonometric Functions: Unit Circle Approach/15 - Revision history

Manuelg70564@students.laalliance.org at 19:29, 30 August 2022

2022-08-30T19:29:38Z

← Older revision		Revision as of 19:29, 30 August 2022
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	\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{2\sqrt{21}}{21}		\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{5\sqrt{21}}{21}\\[2ex]
	\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]
	\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]		\cos{(t)}&= -\frac{2}{5} & \sec{(t)} &= \frac{5}{-2}\\[2ex]
			\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &=\frac{2\sqrt{21}}{21} \\[2ex]

	\end{align}		\end{align}

Manuelg70564@students.laalliance.org at 19:20, 30 August 2022

2022-08-30T19:20:27Z

← Older revision		Revision as of 19:20, 30 August 2022
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	\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac\5 sqrt{21}{21}~~\\[2ex]~~		\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{2\sqrt{21}}{21}
	\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]		\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]
	\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]		\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]

Manuelg70564@students.laalliance.org at 19:13, 30 August 2022

2022-08-30T19:13:44Z

← Older revision		Revision as of 19:13, 30 August 2022
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	\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex]		\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac\5 sqrt{21}{21}\\[2ex]
	\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]		\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]
	\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]		\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]

Manuelg70564@students.laalliance.org at 18:54, 30 August 2022

2022-08-30T18:54:08Z

← Older revision		Revision as of 18:54, 30 August 2022
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	\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex]		\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex]
	\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]		\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]
	\tan{(t)} &= \frac\sqrt-{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]		\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]

	\end{align}		\end{align}

Manuelg70564@students.laalliance.org at 18:53, 30 August 2022

2022-08-30T18:53:06Z

← Older revision		Revision as of 18:53, 30 August 2022
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	\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex]		\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex]
	\cos{(t)} &= \frac\{x}{r} & \sec{(t)} &= \frac{r}{x}\\[2ex]		\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]
	\tan{(t)} &= \frac{y}{x} & \cot{(t)} &= \frac{x}{y} \\[2ex]		\tan{(t)} &= \frac\sqrt-{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]

	\end{align}		\end{align}

Manuelg70564@students.laalliance.org: Created page with ": $\begin{align} -\frac{2}{5},\frac\sqrt{21}{5} \sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex] \cos{(t)} &= \frac\{x}{r} & \sec{(t)} &= \frac{r}{x}\\[2ex] \tan{(t)} &= \frac{y}{x} & \cot{(t)} &= \frac{x}{y} \\[2ex] \end{align}$ \end{align} "

2022-08-30T18:48:22Z

Created page with ":<math> \begin{align} -\frac{2}{5},\frac\sqrt{21}{5} \sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex] \cos{(t)} &= \frac\{x}{r} & \sec{(t)} &= \frac{r}{x}\\[2ex] \tan{(t)} &= \frac{y}{x} & \cot{(t)} &= \frac{x}{y} \\[2ex] \end{align} </math> \end{align} </math>"

New page

:<math>
\begin{align}
-\frac{2}{5},\frac\sqrt{21}{5}

\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex]
\cos{(t)} &= \frac\{x}{r} & \sec{(t)} &= \frac{r}{x}\\[2ex]
\tan{(t)} &= \frac{y}{x} & \cot{(t)} &= \frac{x}{y} \\[2ex]

\end{align}
</math>

\end{align}
</math>