6.2 Trigonometric Functions: Unit Circle Approach/113 - Revision history

Hannag101602@students.laalliance.org at 23:27, 13 September 2022

2022-09-13T23:27:20Z

← Older revision		Revision as of 23:27, 13 September 2022
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	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(p\circ g)(315^{\circ})= \cos(315^{\circ}~~)\frac~~{2} </math>		<math>(p\circ g)(315^{\circ})= \frac{{cos(315^{\circ}}{2} </math>

2022-09-13T23:19:38Z

← Older revision		Revision as of 23:19, 13 September 2022
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	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(p\circ g)(315^{\circ})= \cos(315^{\circ}) </math>		<math>(p\circ g)(315^{\circ})= \cos(315^{\circ})\frac{2} </math>

2022-09-13T23:18:47Z

← Older revision		Revision as of 23:18, 13 September 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(p\circ g)(315^{\circ})= \cos(315^{\circ})		<math>(p\circ g)(315^{\circ})= \cos(315^{\circ}) </math>

2022-09-13T23:18:21Z

← Older revision		Revision as of 23:18, 13 September 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(p\circ g)(315^{\circ})=~~h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}~~\~~right)=h~~(30^{\circ})~~=2\cdot30^{\circ}=60^{\circ}</math>~~		<math>(p\circ g)(315^{\circ})= \cos(315^{\circ})

2022-09-13T23:16:53Z

← Older revision		Revision as of 23:16, 13 September 2022
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	<math>h(x)=2x</math><br>		<math>h(x)=2x</math><br>
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

			<math>(p\circ g)(315^{\circ})=h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}\right)=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>

2022-09-06T20:05:44Z

Created page with "<math>f(x)=\sin(x)</math> <math>g(x)=\cos(x)</math> <math>h(x)=2x</math> <math>p(x)=\frac{x}{2}</math> "

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