6.2 Trigonometric Functions: Unit Circle Approach/112 - Revision history

Kevind75816@students.laalliance.org at 16:24, 7 September 2022

2022-09-07T16:24:25Z

← Older revision		Revision as of 16:24, 7 September 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(f\~~cdot g~~)(60^{\circ})=h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}\right)=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>		<math>(g\circ p)(60^{\circ})=h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}\right)=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>

2022-09-07T16:21:01Z

← Older revision		Revision as of 16:21, 7 September 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(h\~~circ p~~)(60^{\circ})=h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}\right)=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>		<math>(f\cdot g)(60^{\circ})=h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}\right)=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>

2022-08-26T17:28:21Z

← Older revision		Revision as of 17:28, 26 August 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(h\circ p)(60^{\circ})=h(p(60^{\circ})=h(\frac{60^{\circ}}{2})=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>		<math>(h\circ p)(60^{\circ})=h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}\right)=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>

2022-08-26T17:28:04Z

← Older revision		Revision as of 17:28, 26 August 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(h\circ p)(60^{\circ})=h(p(60^{\circ})</math>		<math>(h\circ p)(60^{\circ})=h(p(60^{\circ})=h(\frac{60^{\circ}}{2})=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>

2022-08-26T17:26:21Z

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2022-08-26T17:25:50Z

2022-08-26T17:24:47Z

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2022-08-26T17:21:45Z

Created page with "<math>f(x)=\sin(x)</math> <math>g(x)=\cos(x)</math> <math>h(x)=2x</math> <math>p(x)=\frac{x}{2}</math> "

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