6.2 Trigonometric Functions: Unit Circle Approach/109 - Revision history

Kevind75816@students.laalliance.org at 15:48, 8 September 2022

2022-09-08T15:48:08Z

← Older revision		Revision as of 15:48, 8 September 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(f\cdot g)(\frac{3\pi}{4})=f(g(\frac{3\pi}{4})=f\left(\frac{~~30^~~{~~\circ~~}}{2}\right)=~~h(15^{~~\~~circ})=2\cdot15^~~{~~\circ~~}~~=30^~~{~~\circ~~}</math>		<math>(f\cdot g)(\frac{3\pi}{4})=f(g(\frac{3\pi}{4})=f\left(-\frac{\sqrt{2}}{2}\right)= -\frac{1}{2}
			</math>

2022-09-08T15:45:14Z

← Older revision		Revision as of 15:45, 8 September 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(f\cdot g)(\frac{3\pi}{4})=f(g(\frac{3\pi}{4})=h\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>		<math>(f\cdot g)(\frac{3\pi}{4})=f(g(\frac{3\pi}{4})=f\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>

2022-09-08T15:40:29Z

← Older revision		Revision as of 15:40, 8 September 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(f\cdot g)(\frac{3\pi}{4})=h(p(~~30^~~{\~~circ~~})=h\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>		<math>(f\cdot g)(\frac{3\pi}{4})=f(g(\frac{3\pi}{4})=h\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>

2022-09-07T21:06:16Z

← Older revision		Revision as of 21:06, 7 September 2022
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(f\cdot g)(~~30^~~{\~~circ~~})=h(p(30^{\circ})=h\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>		<math>(f\cdot g)(\frac{3\pi}{4})=h(p(30^{\circ})=h\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>

2022-09-07T16:26:07Z

← Older revision		Revision as of 16:26, 7 September 2022
Line 3:		Line 3:
	<math>h(x)=2x</math><br>		<math>h(x)=2x</math><br>
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

			<math>(f\cdot g)(30^{\circ})=h(p(30^{\circ})=h\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>

2022-09-07T16:19:31Z

Created page with "<math>f(x)=\sin(x)</math> <math>g(x)=\cos(x)</math> <math>h(x)=2x</math> <math>p(x)=\frac{x}{2}</math> "

New page