6.1 Areas Between Curves/14 - Revision history

Josuem95981@students.laalliance.org at 19:38, 20 September 2022

2022-09-20T19:38:20Z

← Older revision		Revision as of 19:38, 20 September 2022
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	\begin{align}		\begin{align}

	& \color{purple}\mathbf{y=\cos(x)}, y=2-\cos(x)\\		& \color{purple}\mathbf{y=\cos(x)}, \color{green}\mathbf{y=2-\cos(x)}\\
	& \int_{0}^{2\pi} \left[2 - \cos(x) - \cos(x) \right]\mathrm{d}x = \int_{0}^{2\pi} \left[2 - 2\cos(x)\right]\mathrm{d}x\\		& \int_{0}^{2\pi} \left[2 - \cos(x) - \cos(x) \right]\mathrm{d}x = \int_{0}^{2\pi} \left[2 - 2\cos(x)\right]\mathrm{d}x\\
	&= \left[ 2x-2\sin(x) \right]\bigg\|_{0}^{2\pi}\\		&= \left[ 2x-2\sin(x) \right]\bigg\|_{0}^{2\pi}\\

Josuem95981@students.laalliance.org at 19:37, 20 September 2022

2022-09-20T19:37:50Z

← Older revision		Revision as of 19:37, 20 September 2022
Line 6:		Line 6:
	\begin{align}		\begin{align}

	& y=\cos(x), y=2-\cos(x)\\		& \color{purple}\mathbf{y=\cos(x)}, y=2-\cos(x)\\
	& \int_{0}^{2\pi} \left[2 - \cos(x) - \cos(x) \right]\mathrm{d}x = \int_{0}^{2\pi} \left[2 - 2\cos(x)\right]\mathrm{d}x\\		& \int_{0}^{2\pi} \left[2 - \cos(x) - \cos(x) \right]\mathrm{d}x = \int_{0}^{2\pi} \left[2 - 2\cos(x)\right]\mathrm{d}x\\
	&= \left[ 2x-2\sin(x) \right]\bigg\|_{0}^{2\pi}\\		&= \left[ 2x-2\sin(x) \right]\bigg\|_{0}^{2\pi}\\

Josuem95981@students.laalliance.org at 19:34, 20 September 2022

2022-09-20T19:34:10Z

← Older revision		Revision as of 19:34, 20 September 2022
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			[[File:Desmos-graph2.png\|300px\|left]]



	<math>		<math>
	\begin{align}		\begin{align}

Josuem95981@students.laalliance.org: Created page with " $\begin{align} & y=\cos(x), y=2-\cos(x)\\ & \int_{0}^{2\pi} \left[2 - \cos(x) - \cos(x) \right]\mathrm{d}x = \int_{0}^{2\pi} \left[2 - 2\cos(x)\right]\mathrm{d}x\\ &= \left[ 2x-2\sin(x) \right]\bigg|_{0}^{2\pi}\\ &= \left(4\pi - 0 \right) - \left(0\right)\\ &= 4\pi \end{align}$ "

2022-09-19T00:21:50Z

Created page with "<math> \begin{align} & y=\cos(x), y=2-\cos(x)\\ & \int_{0}^{2\pi} \left[2 - \cos(x) - \cos(x) \right]\mathrm{d}x = \int_{0}^{2\pi} \left[2 - 2\cos(x)\right]\mathrm{d}x\\ &= \left[ 2x-2\sin(x) \right]\bigg|_{0}^{2\pi}\\ &= \left(4\pi - 0 \right) - \left(0\right)\\ &= 4\pi \end{align} </math>"

New page

<math>
\begin{align}

& y=\cos(x), y=2-\cos(x)\\
& \int_{0}^{2\pi} \left[2 - \cos(x) - \cos(x) \right]\mathrm{d}x = \int_{0}^{2\pi} \left[2 - 2\cos(x)\right]\mathrm{d}x\\
&= \left[ 2x-2\sin(x) \right]\bigg|_{0}^{2\pi}\\
&= \left(4\pi - 0 \right) - \left(0\right)\\
&= 4\pi

\end{align}
</math>