6.1 Angles and Their Measure/41 - Revision history

Manuelg70564@students.laalliance.org at 22:16, 25 August 2022

2022-08-25T22:16:02Z

← Older revision		Revision as of 22:16, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3}}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3}\cdot \cancel{3}		{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cdot\cancel{3}}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot\cancel 3}

	= {\pi}		= {\pi}

	</math>		</math>

Manuelg70564@students.laalliance.org at 22:13, 25 August 2022

2022-08-25T22:13:05Z

← Older revision		Revision as of 22:13, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3}}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3}\cdot \cancel{3		{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3}}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3}\cdot \cancel{3}

	= {\pi}		= {\pi}

	</math>		</math>

Manuelg70564@students.laalliance.org at 22:12, 25 August 2022

2022-08-25T22:12:41Z

← Older revision		Revision as of 22:12, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3}}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}		{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3}}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3}\cdot \cancel{3

	= {\pi}		= {\pi}

	</math>		</math>

Manuelg70564@students.laalliance.org at 22:05, 25 August 2022

2022-08-25T22:05:07Z

← Older revision		Revision as of 22:05, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	{180^{\circ}}=\frac{(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}		{180^{\circ}}=\frac{\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3}}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}

	= {\pi}		= {\pi}

	</math>		</math>

Manuelg70564@students.laalliance.org at 22:04, 25 August 2022

2022-08-25T22:04:04Z

← Older revision		Revision as of 22:04, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	{180^{\circ}}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}		{180^{\circ}}=\frac{(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}

	= {\pi}		= {\pi}

	</math>		</math>

Manuelg70564@students.laalliance.org at 22:02, 25 August 2022

2022-08-25T22:02:45Z

← Older revision		Revision as of 22:02, 25 August 2022
Line 2:		Line 2:
	{180^{\circ}}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}		{180^{\circ}}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}

	= ~~-\frac~~{\pi~~}{3~~}		= {\pi}

	</math>		</math>

Manuelg70564@students.laalliance.org at 22:01, 25 August 2022

2022-08-25T22:01:25Z

← Older revision		Revision as of 22:01, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	{180^{\circ}}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}		{180^{\circ}}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3}\cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}

	= -\frac{\pi}{3}		= -\frac{\pi}{3}

	</math>		</math>

Manuelg70564@students.laalliance.org at 22:00, 25 August 2022

2022-08-25T22:00:29Z

← Older revision		Revision as of 22:00, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
	{180^{\circ}~~}{\pi~~}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}		{180^{\circ}}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}

	= -\frac{\pi}{3}		= -\frac{\pi}{3}

	</math>		</math>

Manuelg70564@students.laalliance.org at 21:59, 25 August 2022

2022-08-25T21:59:29Z

← Older revision		Revision as of 21:59, 25 August 2022
Line 1:		Line 1:
	<math>		<math>
			{180^{\circ}}{\pi}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}
	180^{\circ}~~\cdot\frac~~{\pi~~}{180^{\circ}~~}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}

	= -\frac{\pi}{3}		= -\frac{\pi}{3}

	</math>		</math>

Manuelg70564@students.laalliance.org: Created page with " $180^{\circ}\cdot\frac{\pi}{180^{\circ}}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3} = -\frac{\pi}{3}$ "

2022-08-25T21:58:11Z

Created page with "<math> 180^{\circ}\cdot\frac{\pi}{180^{\circ}}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3} = -\frac{\pi}{3} </math>"

New page

<math>

180^{\circ}\cdot\frac{\pi}{180^{\circ}}=\frac{-(\cancel{2}\cdot \cancel{2}\cdot \cancel{5}\cdot \cancel{3})}{1}\cdot\frac{\pi}{\cancel{2}\cdot \cancel{2} \cdot \cancel{5} \cdot \cancel{3} \cdot 3}

= -\frac{\pi}{3}

</math>