5.4 Indefinite Integrals and the Net Change Theorem/13 - Revision history

Dvaezazizi@laalliance.org: Protected "5.4 Indefinite Integrals and the Net Change Theorem/13" ([Edit=Allow only administrators] (indefinite) [Move=Allow only administrators] (indefinite))

2022-09-21T19:39:37Z

Protected "5.4 Indefinite Integrals and the Net Change Theorem/13" ([Edit=Allow only administrators] (indefinite) [Move=Allow only administrators] (indefinite))

← Older revision	Revision as of 19:39, 21 September 2022
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2022-09-13T17:36:58Z

← Older revision		Revision as of 17:36, 13 September 2022
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	<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+C</math>		<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+C</math>


	<math>\text{Note: } \int\sinh(x)dx=\cosh(x)+C</math>		<math>\text{Note: } \int\sinh(x)dx=\cosh(x)+C</math>

2022-09-13T17:36:50Z

← Older revision		Revision as of 17:36, 13 September 2022
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	<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+C</math>		<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+C</math>

	<math>\text{~~Indefinite integrals used~~: } \int(\sinh(x))dx=\cosh(x)+C</math>		<math>\text{Note: } \int\sinh(x)dx=\cosh(x)+C</math>

2022-09-13T17:36:35Z

← Older revision		Revision as of 17:36, 13 September 2022
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	<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+C</math>		<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+C</math>

	<math>\text{Indefinite integrals used }~~</math>~~		<math>\text{Indefinite integrals used: } \int(\sinh(x))dx=\cosh(x)+C</math>
	~~<math>\int(\sin(x))dx=-\cos(x)+C</math>~~
	~~<math>~~\int(\sinh(x))dx=\cosh(x)+C</math>

2022-09-13T17:36:12Z

← Older revision		Revision as of 17:36, 13 September 2022
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	<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+c</math>		<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+C</math>

	<math>\text{Indefinite integrals used }</math>		<math>\text{Indefinite integrals used }</math>
	<math>\int(\sin(x))dx=-\cos(x)+C</math>		<math>\int(\sin(x))dx=-\cos(x)+C</math>
	<math>\int(\sinh(x))dx=\cosh(x)+C</math>		<math>\int(\sinh(x))dx=\cosh(x)+C</math>

2022-09-13T17:36:00Z

← Older revision		Revision as of 17:36, 13 September 2022
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	<math>\text{Indefinite integrals used }</math>		<math>\text{Indefinite integrals used }</math>
	<math>\~~int_{}^{}~~(\sin(x))dx=-\cos(x)+C</math>		<math>\int(\sin(x))dx=-\cos(x)+C</math>
	<math>\~~int_{}^{}~~(\sinh(x))dx=\cosh(x)+C</math>		<math>\int(\sinh(x))dx=\cosh(x)+C</math>

2022-09-13T17:35:49Z

← Older revision		Revision as of 17:35, 13 September 2022
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	<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+c</math>		<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+c</math>

	<math>\text{Indefinite integrals used }</math~~> <br><br~~>		<math>\text{Indefinite integrals used }</math>
	<math>\int_{}^{}(\sin(x))dx=-\cos(x)+C</math~~> <br><br~~>		<math>\int_{}^{}(\sin(x))dx=-\cos(x)+C</math>
	<math>\int_{}^{}(\sinh(x))dx=\cosh(x)+C</math>		<math>\int_{}^{}(\sinh(x))dx=\cosh(x)+C</math>

2022-09-13T17:35:38Z

← Older revision		Revision as of 17:35, 13 September 2022
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	<math>\~~int_{}^{}~~(\sin(x)+\sinh(x))dx ~~\qquad \qquad \qquad \qquad \qquad \qquad \qquad \text{Indefinite integrals used }</math> <br><br> <math>=\int_{}^{}(\sin(x))dx+\int_{}^{}(\sinh(x))dx</math> <br><br>~~		<math>\int(\sin(x)+\sinh(x))dx =-\cos(x)+\cosh(x)+c</math>
	~~<math>~~=-\cos(x)+\cosh(x)+c</math~~> <br><br>~~
	~~<br><br~~>

	<math>\text{Indefinite integrals used }</math> <br><br>		<math>\text{Indefinite integrals used }</math> <br><br>
	<math>\int_{}^{}(\sin(x))dx=-\cos(x)+C</math> <br><br>		<math>\int_{}^{}(\sin(x))dx=-\cos(x)+C</math> <br><br>
	<math>\int_{}^{}(\sinh(x))dx=\cosh(x)+C</math>		<math>\int_{}^{}(\sinh(x))dx=\cosh(x)+C</math>

2022-08-30T19:32:27Z

← Older revision		Revision as of 19:32, 30 August 2022
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	<math>\int_{}^{}(\sin(x)+\sinh(x))dx \qquad \qquad \qquad \qquad \qquad \qquad \qquad \text{Indefinite integrals used }</math>		<math>\int_{}^{}(\sin(x)+\sinh(x))dx \qquad \qquad \qquad \qquad \qquad \qquad \qquad \text{Indefinite integrals used }</math> <br><br> <math>=\int_{}^{}(\sin(x))dx+\int_{}^{}(\sinh(x))dx</math> <br><br>
	<math>=\int_{}^{}(\sin(x))dx+\int_{}^{}(\sinh(x))dx</math> <br><br>
	<math>=-\cos(x)+\cosh(x)+c</math> <br><br>		<math>=-\cos(x)+\cosh(x)+c</math> <br><br>
	<br><br>		<br><br>

2022-08-30T19:31:58Z

← Older revision		Revision as of 19:31, 30 August 2022
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	<math>\int_{}^{}(\sin(x)+\sinh(x))dx \qquad \qquad \qquad \qquad \qquad \qquad \qquad \text{Indefinite integrals used }</math> ~~<br><br>~~<math>=\int_{}^{}(\sin(x))dx+\int_{}^{}(\sinh(x))dx</math> <br><br>		<math>\int_{}^{}(\sin(x)+\sinh(x))dx \qquad \qquad \qquad \qquad \qquad \qquad \qquad \text{Indefinite integrals used }</math>
			<math>=\int_{}^{}(\sin(x))dx+\int_{}^{}(\sinh(x))dx</math> <br><br>
	<math>=-\cos(x)+\cosh(x)+c</math> <br><br>		<math>=-\cos(x)+\cosh(x)+c</math> <br><br>
	<br><br>		<br><br>