2024/G2/15 - Revision history

Aroldog69360@students.laalliance.org: Created page with " $\mathbf{3.3}$
$\lim_{\theta\to 0} \frac{sin(\theta)}{\theta} = 1$
$\lim_{\theta\to 0} \frac{cos(\theta)-1}{\theta}=0$
$\frac{d}{dx} [sin(x)] = cos(x)$

$\frac{d}{dx} [cos(x)] = -sin(x)$

$\frac{d}{dx} [tan(x)] = sec^{2}(x)$

$\frac{d}{dx} [csc(x)] = -csc(x) \cdot cot(x)$

$\frac{d}{dx} [sec(x)] = sec(x) \cdot tan(x)$

2023-05-03T15:59:35Z

Created page with "<math>\mathbf{3.3}</math><br> <math> \lim_{\theta\to 0} \frac{sin(\theta)}{\theta} = 1</math><br> <math> \lim_{\theta\to 0} \frac{cos(\theta)-1}{\theta}=0 </math><br> <math> \frac{d}{dx} [sin(x)] = cos(x) </math><br><br> <math> \frac{d}{dx} [cos(x)] = -sin(x) </math><br><br> <math> \frac{d}{dx} [tan(x)] = sec^{2}(x) </math><br><br> <math> \frac{d}{dx} [csc(x)] = -csc(x) \cdot cot(x) </math><br><br> <math> \frac{d}{dx} [sec(x)] = sec(x) \cdot tan(x) </math><br><br> <math..."

New page
<math>\mathbf{3.3}</math><br>

<math> \lim_{\theta\to 0} \frac{sin(\theta)}{\theta} = 1</math><br>
<math> \lim_{\theta\to 0} \frac{cos(\theta)-1}{\theta}=0 </math><br>
<math> \frac{d}{dx} [sin(x)] = cos(x) </math><br><br>
<math> \frac{d}{dx} [cos(x)] = -sin(x) </math><br><br>
<math> \frac{d}{dx} [tan(x)] = sec^{2}(x) </math><br><br>
<math> \frac{d}{dx} [csc(x)] = -csc(x) \cdot cot(x) </math><br><br>
<math> \frac{d}{dx} [sec(x)] = sec(x) \cdot tan(x) </math><br><br>
<math> \frac{d}{dx} [cot(x)] = -csc^{2}(x) </math><br><br>

<math>\mathbf{\color{Blue}{Examples}}</math><br><br>

<math>\mathbf{\color{MidnightBlue}{Ex.2}}</math><br>
<math> f(x)= \frac{sec(x)}{1+tan(x)}
f^\prime(x)= \frac{[sec(x)tan(x)][1+tan(x)]-sec(x)[sec^{2}(x)]}{[1+tan(x)]^2}
= \frac{sec(x)[tan(x)+tan^{2}(x)-sec^{2}(x)]}{(1+tan(x))^{2}} = sec(x)[tan(x)+tan^{2}(x)-[tan^{2}(x)+1] </math><br><br>